What is the total anion concentration (in meq/l) of a solution that contains 6.0 meq/lna+ , 11.0 meq/lca2+ , and 3.0 meq/lli+ ?

We know that each equivalent of Na+ will be combined with one equivalent of anion concentration

Each equivalent of Ca+2 will combine with one equivalent of anion

each equivalent of Li+ will combine with one equivalent of anion

As we are given with 6.0 meq/lna+ , 11.0 meq/lca2+ , and 3.0 meq/lli+ ?

So for each  6.0 meq/l  Na+, the anion concentration will be 6.0 meq/l

So for each  11 meq/l Ca+2 , the anion concentration will be 11meq/l

So for each  3.0 meq/l Li+ , the anion concentration will be 3 meq/l

Thus total anion concentration = 6 + 11 + 3 = 20 meq/l

to make a supersaturated solution, make a saturated solution of sugar by adding 360 grams of sugar to 100 ml of water at 80 degrees celsius. when the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water should only dissolve 210 grams of sugar.