The elements cu, o, la, y, ba, tl, and bi are all found in high-temperature ceramic superconductors. write the expected electron configuration for these atoms. (type your answer in noble gas notation using the format [ar] 4s2 3d10 4p3 for [ar] 4s2 3d10 4p3.)

Part 1)
Cu- [Ar] 3d¹⁰4s¹     atomic number: 29

O-  [He] 2s2 2p4     atomic number:8

La- [Xe] 5d¹ 6s²      atomic number:57

Y-   [Kr] 4d¹5s²      atomic number:39
 
Ba- [Xe] 6s²      atomic number:56

Tl-  [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p¹   atomic number:81

Bi- [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p³ atomic number:83

Part 2)
You are able to this by consulting the periodic table and following this steps:
-Find your atom's atomic number;
-Determine the charge of the atom (these were all uncharged)
-Memorize the order of orbitals (s, d, p, d.. and how many electrons they can fit)
-Fill in the orbitals according to the number of electrons in the atom
- for long electron configurations, abbreviate with the noble gases

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.