5(x-4)+3x-9x=6-(2x+5)+8x
It says to use the distibutive property so what do I do

Multiply the numbers inside the parenthesis with the number outside. In the case of the negative, use -1

Step-by-step explanation:

5(x-4)+3x-9x=6-(2x+5)+8x

5(x)- 5(4) +3x-9x=6 -(2x)-(5)+8x

5x-20+3x-9x=6-2x-5+8x

-x-20=6x+1

-x-6x=20+1

-7x=21

-7x/-7=21/-7

x=-3

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

not sure but it may be b, as i said i'm not sure.