Chemistry, 21.09.2021 20:50 lailahussain99
A sample of aluminum sulfate 18-hydrate, Al2(SO4)3•18H20, containing 170.8 mg is dissolved in 1.000 L of solution.
a. Calculate the molarity of Al2(SO4)3
Molarity =M
b. Calculate the molarity of SO42-
Molarity =M
c. Calculate the molality of Al2(SO4)3, assuming that the density of the solution is 1.000 g/mL.
Molalitym
Answers: 2
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A sample of aluminum sulfate 18-hydrate, Al2(SO4)3•18H20, containing 170.8 mg is dissolved in 1.000...
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