Calculate the heat when 100.0 mL of 0.500 M HCl is mixed with 300.0 mL of 0.100 M Ba(OH)2. Assuming that the temperature of both solutions was initially 25.0C and that the final mixture has a mass of 400.0 g and a specific heat capacity of 4.18 J/C g, calculate the final temperature of the mixture.

26.8°C

Explanation:

For this reaction, the equation can be computed as follows:

Now, Given that:

100.0 mL of 0.500 molarity (M) of HCl reacted with 300.0 mL of 0.100 molarity of Ba(OH)2.

The next process is to determine the number of moles of the solute:

For HCl:

no of mole  =

= 0.05 mol

For Ba(OH)2:

no of mole =

= 0.03 mol

From the reaction, at the reactant side, we will see that two moles of HCl reacted with one mole of Ba(OH)2.

It implies that HCl is the limiting agent since it is in lesser quantity.

Similarly, the heat given out of the system is 118 kJ for each two moles of HCl with one mole of B(OH)2.

Hence, for 0.05 moles of HCl, the heat emitted out is:

= 2.95 kJ

Let's recall from the question that:

the heat emitted was moved to the final mixture with mass =400g

the specific heat capacity = 4.18 J/°C g

Initial temperature = 25°C

∴

Using the formula;

ΔH = mass × specific heat capacity × (T_f - T_i)

Then, replacing the values, we have:

2.95 kJ = 400 g ×  4.18 J/°C g × ( T_f - 25° C)

2950 J = 400 ×  4.18 J/°C × ( T_f - 25° C)

the answer is a. co2, this would be colder than the : )

explanation:

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".