How many grams of S206 are in 17.7 moles of S206?

2721.02 g

Explanation:

you need the molar mass of the compound to solve this

S2O6's molar mass: 2(S) + 6(O)

Sulfur (S) molar mass: 32.06

Oxygen (O) molar mass: 15.99

2(32.06) + 6(15.99) --> 64.12 + 95.94 = 160.06 g/mol

We want to know how much of it is in 17.7 moles, so you perform the following stoichiometry

160.06 g/mol * 17.7 mol

mol units cancel out and we are left with g.

160.06 * 17.7 = 2721.02 g of S2O6 in 17.7 moles of it

 The correct answer is 2721.02 g

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.