Which of the following best describe the particles present in a 2.0 m aqueous solution of al(no3)3? 2 m al(no3)3(aq)2 m al3+(aq) and 6 m no3-(aq)2 m al3+(aq) and 3 m no3-(aq)2 m al3+(aq) and 18 m no3-(aq)

2,0 M of Al³⁺ and 6,0M of NO₃⁻.

Explanation:

In water, Al(NO₃)₃ dissociates as follows:

Al(NO₃)₃ → Al³⁺ + 3 NO₃⁻

That means in water, you will have 1 mole of Al³⁺ and 3 moles of NO₃⁻ per mole of Al(NO₃)₃.

Now, as the solution of Al(NO₃)₃ is 2,0M, you will have

2,0 M of Al³⁺ and 6,0M of NO₃⁻.

I hope it helps!