How many liters of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K?

A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Explanation:

Given: Mass of Mg = 2.3 g

Pressure = 2 atm

Temperature = 298 K

The reaction equation is as follows.

This shows that 1 mole of Mg gives 1 mole of .

Hence, moles of Mg for the given mass is calculated as follows.

Hence, 0.095 moles of Mg will give 0.095 moles of .

Formula used to calculate volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890