How much water can be produced when 18 grams of pentane is burned in air? C5H12 + 8 02 --> 5 CO2 + 6 H2O. 9.0 g 18 g 27 g 36 g 729

The mass of water produced is 27 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

......(1)

Given mass of pentane = 18 g

Molar mass of pentane = 72.15 g/mol

Plugging values in equation 1:

The given chemical equation follows:

By the stoichiometry of the reaction:

If 1 mole of pentane produces 6 moles of water

So, 0.250 moles of pentane will produce = of water

Molar mass of water = 18 g/mol

Plugging values in equation 1:

Hence, the mass of water produced is 27 g

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles