What is the mass, in grams, of 0.250 mol K2CO3?

jug

Explanation:

34.55 g

Explanation:

n = m/mm

mm of k2co3 = 138.21 gmol

0.250 = m/(2 x 39.1) + 12.01 +(3 x 16)

0.250 mol = mass/ 138.21 gmol

mass = 0.25mol x 138.21 gmol

mass = 34.5525 g

mass = 34.55 (2dp) g

answer; natural resources;

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.