Hurry will give points The table shows the battery lives, in hours, of ten Brand A batteries and ten Brand B batteries. Which would be the best measure of variability to use to compare the data? Only Brand A data is symmetric, so standard deviation is the best measure to compare variability. Only Brand B data is symmetric, so the median is the best measure to compare variability. Both distributions are symmetric, so the mean is the best measure to compare variability. Both distributions are skewed left, so the interquartile range is the best measure to compare variability

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

yes, gavin is right.

step-by-step explanation:

gavin is correct. 

this problem is about converting 9% per year to how many percent per quarter. the rate is still the same. it only differed in the time period. so, through dimensional analysis,

9% per year  × (1 year / 4 quarters) = 2.25% per quarter

if he was asked to convert 9% per year to how many percent per quarter  compounded quarterly, then you will not simply divide by four. this is because compounding is not linear.

hope this , have a good day. c;