If the temperature of 85.0 g of copper changes from 28.0°C to 99.0°C, how much heat was absorbed? The specific heat capacity of copper is 0.385 J/K:g. Write your
answer to 3 sig figs.

2320 J

Explanation:

We'll begin by calculating the change in temperature of the copper. This can be obtained as follow:

Initial temperature (T₁) = 28.0 °C

Final temperature (T₂) = 99.0 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 99 – 28

ΔT = 71 °C

Finally, we shall determine the heat absorbed by the copper. This can be obtained as follow:

Mass of copper (M) = 85 g

Change in temperature (ΔT) = 71 °C

Specific heat capacity (C) = 0.385 J/K.g

Heat (Q) absorbed =?

Q = MCΔT

Q = 85 × 0.385 × 71

Q = 2320 J

Thus, the heat absorbed is 2320 J

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