Hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(g) H2(g) I2(g) K for the reaction is 0.016. Of 0.148 atm of HI(g) is sealed in a flask, what is the pressure of each gas when equilibrium is established

Solution :

Given :

Hydrogen iodide decomposes to hydrogen and iodine gas

I    0.148            0          0

C     -2a           +a          +a

E  0.148-2a      a            a

We know

0.0187 = 1.2529 a

a = 0.0149

Therefore

P(HI) = 0.148 - 2a

        = 0.148 - 2(0.0149)

        = 0.1182 atm

P() =  a

        = 0.0149 atm

P() =  a

        = 0.0149 atm

you gotta add the following molecules so we can give u an answer

explanation: