Part D Repeat the procedure from part C to complete three more trials. The temperature of the hot water in each trial should be
the same as the temperature of the hot water in part C. But the cold water should be at a different temperature than in
part C. Use any three temperature points between 15°C and 35°C (59°F and 95°F). Record your data in the table.
B U
Font Sizes A- A-EE
7
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Trial 4
Trial 5
Trial 6
Hot Temperature (°C)
Cold Temperature (°C)
Water Volume (mL)

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

the correct answer to this question is 2