If 832j of energy is required to raise the temperature of a sample of aluminum from 20.0°c to 97.0°c, what mass is the sample of aluminum? (the specific heat of aluminum is 0.90 j/(g × ° 0.10 g 10.0 g 12.0 g 57.7 g

Given:
The energy required is
 Q = 832 J
The temperature rise is
 ΔT = 97 - 20 C
      =  77 C = 77 K
The specific heat is
 c = 0.9 J/(g-C)
    = (0.9 J/(g-K)*(1000 g/kg)
    = 900 J/(kg-K)

Let the mass be m kg.
Then
(m kg)*(c J/(kg-K))*(ΔT K) = (Q J)
or
900*77*m = 832
m = 0.012 kg = 12 g

 The mass of aluminum is 12.0 g

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