What mass of silver nitrate, agno3, is required to prepare 800. g of 3.50% solution of agno3

28 g of AgNo3

Explanation:

800 g of 3.5% solution of AgNo3 is to be prepared.

3.5% AgNo3 solution contains 3.5g of AgNo3 in 100 g of solution.

If 3.5 g AgNo3 is present in 100 g of solution, then how many g is needed to make 800 g of solution?

       3.5 g AgNo3100 g solution

        X g AgNo3 800 g solution

    X g AgNo3 = 3.5 x 800/100

                             = 28 g

Hence, 28 g of AgNo3 will be required to prepare 800 g of 3.5% solution of AgNo3.