What amount of heat is removed to lower the temperature of 80 grams of water from 75º c to 45º c? the specific heat of liquid water is 4.18 j/gº c.
a. -10,000 j
b. 10,000 j
c. -8,000 j
d. 8,000 j

The correct answer option A.

Explanation:

Q= heat removed from the water

m= mass of the water = 80 grams

c = heat capacity of water= 4.18 J/g°C      

Q = -10,032 joules -10,000 Joules

Negative sign indicates that heat was removed from the water.

Heat removed from the water of 80 gram of water is 10,032 Joules.Hence, the correct answer option A.

explanation:

i think option no d is the correct answer