Which function below has the lowest y intercept?
g(x)
al had two dozen donuts when he walked into the office, but every cubicle he passed, he lost 2 donuts.
h(x)
h(x) = 6x + 1
a. f(x)
b. g(x)
c. h(x)
d. the functions all have the same y intercept.

Our first function is g(x). Al had two dozen donuts means that two dozen is the y-intercept of this function. A dozen equals 12, therefore two dozens is 24. Every cubicle he passed, he lost 2 donuts is the slope of the function and it is negative, that is -2, thus:

The second equation is h(x):

So:

From the graph, we can see that the f(x) intersects the y-axis at:

Accordingly, h(x) has the lowest y intercept.

In conclusion, the right answer is c.h(x)

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)