Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are: [NO]=1.2x10^-3M , [NO2]=1.5x10-^1M , [N2O]=2.4x10^-3M

The equilibrium constant is 2.08x10⁵

Explanation:

Based on the reaction:

3NO ⇄ N₂O + NO₂

The equilibrium constant, k, is defined as:

k = [NO₂] [N₂O] / [NO]³

Where the [] is the molarity in equilibrium of each specie.

Computing te values of the problem:

k = [1.5x10⁻¹M] [2.4x10⁻³M] / [1.2x10⁻³M]³

k = 2.08x10⁵

i believe the answer is three water molecules