For the concentration cell, Pb(s) | PbSO4(s), NH4+ (3.0M), SO42-(1.50M), NO3- (0.10M), Pb2+(? M) || Pb(NO3)2(0.05 M) | Pb(s), Ecell = -(0.0257/2)ln(x/0.05), what is the expression for x in terms of Ecell ? {The notation used here is exp[x] = ex where "e" is the base of natural logarithm.}

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.