Can someone help with this question I will big BRAINLEST quick thank you

Charle's Law ... V ∝ f(T); Pressure and Mass remain constant

Explanation:

Charle's Law is one of the empirical gas laws relating the effect of temperature on volume of a gas while pressure and mass (moles) of substance remain constant. Basically, Charle's Law states that the change in volume associated with a confined mass or gas is directly proportional to the applied temperature.

For a directly proportional relationship between Volume (V) and Temperature (T) the empirical formula is written V ∝ T. This is then set in equation form by including a 'proportionality constant' giving V = k·T. In applications, problems generally provide 'initial' Temperature (T₁) and Volume (V₁) along with a final Temperature (T₂) or final Volume (V₂) and asked to calculate the unknown variable. The Charle's Law relationship detailing this is derived as follows:

V = k·T => k = V/T

The k-value is constant for both the initial and final conditions such that...

k₁ = k₂ => V₁/T₁ = V₂/T₂

Example: Assume a gas volume of 25 liters at 25°C, what would be the gas volume if cooled to 0°C?

Set-up a data table

V₁ = 25L     & V₂ = ?

T₁ = 25°C   & T₂ = 0°C => these values need to be converted to Kelvin Temps so as to avoid division by '0'. So...

T₁ = (25 + 273)K = 298K     &     T₂ = (0 + 273)K = 273K

Substituting into V₁/T₁ = V₂/T₂ and solving for V₂ provides the new volume.

25L/298K = V₂/273K => V₂ = (25L)(273K)/(298K) = 22.9L ≅ 23L (2 sig. figs.)

Generally, to check work, examine the change in volume relative to the change in temperature. For a direct proportionality a decrease in temperature as in the example would give a decrease in volume consistent with Charle's Law. Note that 273K/298K  times  25L gives a smaller resulting volume value. If one applies '298K/273K' times the 25L,  a larger value would result and is inconsistent with Charle's Law.  

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

is there any options? maybe im just not seeing them but i need the options to

-love shrooms