4b^2 +8b + 7 = 4

show your work I already have the answer!!

(-.5,0) and (-1.5,0)

or b= -.5

and b= -1.5

Step-by-step explanation:

First we want one side of the equation to equal 0

we have

4b²+8b+3=0

using the quadratic formula we have

(-b±√(b²-4*a*c))/2a

(-8±√(8²-4*4*3))/2*4

(-8±√(16))/8

(-8±4)/8

now we evaulate when ± is addition

(-8+4)/8

-4/8

-.5

and evaulate once more when the ± is subtraction

(-8-4)/8

-12/8

-1.5

Therefore the two solutions are (-.5,0) and (-1.5,0)

Step-by-step explanation:

step one - Move terms to the left side

(4b^2 + 8b + 7 = 4)

(4b^2 + 8b + 7 - 4 = 0)

step dose - Subtract the numbers

(4b^2 + 8b + 3 = 0)

step три - Use the sum-product pattern

(4b^2 + 6b + 2b + 3 = 0)

i think the length is 12 and the width is 17

where are the graphs?

step-by-step explanation: