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Chemistry, 29.03.2021 15:50 ferrin6507

In aqueous solutions there are three forms of glucose: the D-form (36%), the E-form (64%) and a trace amount of the open-chain form. At equilibrium, the alpha and beta cyclic forms are

interconverted by way of the open chain structure. Explain (a) why the cyclic forms exist

predominately in solutions, and (b) why the E-form is more abundant than the D-form.

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In aqueous solutions there are three forms of glucose: the D-form (36%), the E-form (64%) and a tra...
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