Can someone please help me with this

First balance the equation: you get 3Fe + 4H2O = Fe3O4 +4H2O

Then set up the equations according to the spidey map below.

x 10^25 molec. H2O/ 1 x x x

Multiply the top all together, then divide by the whole bottom half.

154.4 g H2

136 g Fe /1 x x x

Multiply the top all together, then divide by the whole bottom half.

4.95 x 10^20 Formula units (fu) Fe3O4

8.25 x 10^23 molec. Fe/ 1 x x

Multiply the top all together, then divide by the whole bottom half.

1.83 mol H2

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm