Find the equation of a circle that passes through (2,0) and (8,0)and also touches the y axis

(x-5)*2 +(y-4)*2=25

Explanation

Equation of circle is (x-a)*2 + (y-b)*2=r*2

Expand equation to get

x*2 - 2ax + y*2- 2by+ b*2= 0

Then take the points and put them into the equation

You will then have two equations

Solve them simultaneously to find a and b

Where a= 5 and b = 4

After put it back to the equation of the circle

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x