When 14 cal of heat are added to 12g of a liquid its temperature rises from 10.4 C to 12.7 C. What is the specific heat of the liquid

0.51 cal/g.°C

Explanation:

Step 1: Given data

Added energy in the form of heat (Q): 14 calMass of the liquid (m): 12 gInitial temperature: 10.4 °CFinal temperature: 12.7 °C

Step 2: Calculate the temperature change

ΔT = 12.7 °C - 10.4 °C = 2.3 °C

Step 3: Calculate the specific heat of the liquid (c)

We will use the following expression.

c = Q / m × ΔT

c = 14 cal / 12 g × 2.3 °C = 0.51 cal/g.°C

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