How many grams are needed to make 2 L of solution of 4 M LiNO3?

552 g of LiNO₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mass of LiNO₃ =?

Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mole of LiNO₃ =?

Molarity = mole /Volume

4 = mole of LiNO₃ / 2

Cross multiply

Mole of LiNO₃ = 4 × 2

Mole of LiNO₃ = 8 moles

Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:

Mole of LiNO₃ = 8 moles

Molar mass of LiNO₃ = 7 + 14 + (16×3)

= 7 + 14 + 48

= 69 g/mol

Mass of LiNO₃ =?

Mole = mass /Molar mass

8 = Molar mass of LiNO₃ /69

Cross multiply

Molar mass of LiNO₃ = 8 × 69

Molar mass of LiNO₃ = 552 g

Thus, 552 g of LiNO₃ is needed to prepare the solution.

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying

no statements shown

the atomic number of carbon is six, which means that a carbon atom has six protons. carbon has three naturally occurring isotopes: carbon-12, carbon-13, and carbon-14. which of these statements are true about carbon and its isotopes? select all that appl