Imagine that each of the three containers in Model 2 contains krypton atoms. The atomic radius of a krypton atom is 88.00 pm. Assuming the atom is a solid sphere, calculate the volume of one krypton atom in liters.

The volume of a krypton atom in liters = 2.86 x 10⁻²⁷ liters

Explanation:

The volume of a sphere is given by the formula below:

V = 4/3 (π)(r³)

where π = 22/7, radius of the krypton atom = 88.00 pm

However, 1 picometre (pm) = 1 x 10⁻¹⁰ cm, converting 88.00 pm to cm will be:

88.00 pm x 10⁻¹⁰ cm/ 1 pm = 88.00 x 10⁻¹⁰ cm

Substituting the values above in order to determine the volume of a krypton atom:

V = 4/3 x (22/7) x (88.00 x 10⁻¹⁰ cm)³

V = 2.86 x 10⁻²⁴ cm³

However, 1000 cm³ = 1 liter

Therefore, 2.86 x 10⁻²⁴ cm³ in liters will be:

2.86 x 10⁻²⁴ cm³/ (1000 cm³/1 liter) = 2.86 x 10⁻²⁷ liters

The volume of a krypton atom in liters = 2.86 x 10⁻²⁷ liters

e

explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j