How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25°C? C°C +273 = °K) (R=0.0821 L. atm/mol-K)

We are given:

Volume of Gas (V) = 2.5L

Pressure (P) = 1.2 atm

Temperature (T) = 25°C  OR 25+273 = 298 K

Universal Gravitational Constant (R) = 0.0821

Solving for number of moles:

From the Ideal Gas Equation,

PV = nRT

(1.2)(2.5) = n(0.0821)(298)           [plugging the given values]

n = [(1.2)(2.5)] / [0.0821*298]

n = 300 / [298*8.21]

n = 0.12 moles

Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C

a chemical reaction happens

explanation: