A chemist adds of a aluminum chloride solution to a reaction flask. Calculate the millimoles of aluminum chloride the chemist has added to the flask. Round your answer to significant digits.

The given question is incomplete. The complete question is:

A chemist adds 245.0 ml 0.0238 M of a aluminum chloride solution to a reaction flask. Calculate the millimoles of aluminum chloride the chemist has added to the flask. Round your answer to two significant digits.

The millimoles of aluminum chloride are 5.8

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = milli moles of solute

= volume of solution in ml

Now put all the given values in the formula of molarity, we get

Therefore, the millimoles of aluminum chloride are 5.8

i think it is true since you can test the answer and can use observations to complete it.