A compound of formula C5H10 gave a 1H NMR spectrum described as follows: δ Multiplicity Integration 1.5 singlet 3H 1.6 singlet 3H 1.7 doublet 3H 5.6 quartet 1H Identify the molecule and write the SMILES string for the structure in the box below. You can use MARVIN sketch or the NIH Online structure editor to get the SMILES string (Click on "start structure editor").

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the correct answer to this question is 2

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally