Acan company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. one of the company’s clients needs a cylindrical can that has the same volume but is 15 cm tall. what must the new radius be to meet the client’s need? round to the nearest tenth of a centimeter.

2.7 cm
4.9 cm
7.3 cm
24.0 cm

  4.9 cm

Step-by-step explanation:

The original can has a volume of ...

  V = πr²h = π(6 cm)²(10 cm) = 360π cm³

The new can will have the same volume, but a different height:

  360π cm³ = πr²(15 cm)

  24 cm² = r² . . . . . divide by 15π cm

  r = √24 cm ≈ 4.9 cm . . . . . take the square root

The new radius must be about 4.9 cm.

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2