Why is the protist kingdom sometimes called the odds and ends kingdom.

Because the members of this realm are so different, making it difficult to classify them taxonomically.

Explanation:

The protist kingdom is formed by the protozoa and the unicellular algae, but now also encompasses some multicellular algae (green, brown and red algae), being called Protoctist. It is the first eukaryotic kingdom (they have nucleus and membranous organelles); It is a polyphyletic kingdom (several ancestors gave rise to groups belonging to this kingdom) and as a consequence was later reclassified and divided into several kingdoms. There are no unique characteristics that define the Protoctist realm, the members of this realm are very different and so this realm is sometimes called "odds and ends".  They have very different characteristics: they can be uni or multicellular, aerobic or anaerobic, photosynthetic autotrophic (algae) or ingestion heterotrophic (protozoa).

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.