What would happen to the particles in illustration A if the substance were chilled?
What would happen if the particles in
illustration B were warmed?

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

ugh fiel iente of insistí is did kiwis jaj

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest