What mass of carbon monoxide gas (CO) would occupy a volume of 4.30 L at STP? Explain how you got the answer.

5.38 g of CO.

Explanation:

From the question given above, the following data were obtained:

Volume of CO = 4.3 L

Mass of CO =?

Next, we shall determine the number of mole of CO that occupied 4.3 L at STP. This can be obtained as follow:

Recall = 1 mole of any gas occupy 22.4 L at STP.

1 mole of CO occupied 22.4 L at STP.

Therefore, Xmol of CO will occupy 4.3 L at STP i.e

Xmol of CO = 4.3 / 22.4

Xmol of CO = 0.192 mole.

Thus, 0.192 mole of CO occupy 4.3 L at STP.

Finally, we shall determine the mass of CO as follow:

Mole of CO = 0.192 mole.

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO =?

Mole = mass /Molar mass

0.192 = mass of CO / 28

Cross multiply

Mass of CO = 0.192 × 28

Mass of CO = 5.38 g.

Therefore, 5.38 g of CO occupied 4.3 L at STP.

the objects have the same charge is correct.

nathan lee

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.