A2.5600 gram sample of a sulfur-containing compound is analyzed by precipitating the sulfur as baso4. if 1.1756 g of baso4 are obtained, what is the percentage of sulfur in the sample?

The percent sulfur in the compound is 6.308 %.

Explanation:

We are given:

Mass of barium sulfate = 1.1756 g

We know that:

Molar mass of barium sulfate = 233.38 g/mol

Molar mass of sulfur atom = 32.07 g/mol

As, all the sulfur in the compound is converted to barium sulfate. So, the mass of sulfur in barium sulfate will be equal to the mass of sulfur present in the compound.

To calculate the mass of sulfur in given mass of barium sulfate, we apply unitary method:

In 233.38 g of barium sulfate, mass of sulfur present is 32.07 g

So, in 1.1756 g of barium sulfate, mass of sulfur present will be =

To calculate the percentage composition of sulfur in compound, we use the equation:

Mass of compound = 2.5600 g

Mass of sulfur = 0.1615 g

Putting values in above equation, we get:

Hence, the percent sulfur in the compound is 6.308 %.

your mom.com . : 0000

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.