When an unknown amount of methane reacts with 40.7 g of chlorine, 40.5 g of methyl chloride and 36.5 g of hydrogen chloride form how much methane was used round to the tenth

36.3 gram

Explanation:

CH₄ + Cl₂ = CH₃Cl + HCl

In any reaction , mass is conserved

mass of product = 40.5 + 36.5 = 77 g

Let methane reacted be x .

mass of reactant = x + 40.7

mass of reactant = mass of product

x + 40.7  = 77

x = 36.3 gram

methane reacted = 36.3 gram.

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