Jillian wants to find the surface area of a pyramid the base is a square with sides that are 4 inches long the other faces are isosceles triangles the ratio of the height of each triangle to its base is 3: 1 part a: give the base length and the height of each triangular face part b : find the combined area of the triangular faces part c: find the surface area of the pyramid

a.Length of base=4 inches

Length of height=12 inches

b.Area of  triangular faces=96 square inches

c.Surface area of pyramid=112 square inches

Step-by-step explanation:

We are given that base of pyramid is square shaped with side 4 inches long

Other faces are isosceles triangles

We are given that ratio of height of each triangle  to its base =3:1

a.We have to find the length of base and the height of each triangular face

Length of base=4 inches

Height is 3 times the base

Therefore, length of height=

b.There are 4 triangular faces

We know that area of triangle=

Using this formula

Area of one triangular face ==24 square inches

Area of 4 triangular faces=

c. Surface area of pyramid=area of 4 triangular faces+area of square

Surface area of pyramid =