Answer? If u can show work if not it’s fine

E = 2.4×10⁻¹⁴J

Frequency =0.36×10²⁰ Hz

Explanation:

Given data:

Wavelength of light = 8.22×10⁻¹² m

Frequency of light = ?

Energy of light = ?

Solution:

peed of light = wavelength× frequency

speed of light = 3×10⁸ m/s

Now we will put the values in formula.

3×10⁸ m/s =  8.22×10⁻¹² m  × frequency

Frequency = 3×10⁸ m/s / 8.22×10⁻¹² m  

Frequency =0.36×10²⁰ s⁻¹

s⁻¹ = Hz

Frequency =0.36×10²⁰ Hz

Energy of light:

Formula:

E = hf

h = planks constant = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Js × 0.36×10²⁰s⁻¹

E = 2.4×10⁻¹⁴J

i would say b

explanation:

but i think i would need more information than that

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante