Researchers measured the data speeds for a particular smartphone carrier at 50 airports. the highest speed measured was 77.577.5 mbps. the complete list of 50 data speeds has a mean of x overbarxequals=17.1517.15 mbps and a standard deviation of sequals=35.8835.88 mbps.
a. what is the difference between carrier's highest data speed and the mean of all 50 data speeds?
b. how many standard deviations is that [the difference found in part (a)]?
c. convert the carrier's highest data speed to a z score.
d. if we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

  or  

sin y = 7/q

7 is the opposite side length, q is the hypotenuse

tan y = 7/r

7 is the opposite side length, r is the adjacent side length

using sohcahtoa ^^^^

cos y = adjacent/hypotenuse

cos y = r/q

you meant circumference well the answer is:

17.27876 miles

area is 23.7583

the radius is 2.75 miles

hope this hmu if needed.