HELP An unknown gas effuses at a rate of 2.0 times the rate of CL2. What is the molar mass of the unknown gas?

Explanation:Explanation:

We can solve this equation using Graham's law of effusion:

r

1

r

2

=

√

M

M

2

M

M

1

We can substitute gas

X

and

oxygen

in for 1 and 2, respectively, to get

r

X

r

O

2

=

√

M

M

O

2

M

M

X

Since

O

2

effuses at a rate twice that of gas

X

, the ratio of the rate of effusion of

X

to

O

2

is

0.5

:

0.5

=

√

M

M

O

2

M

M

X

Since the molar mass of

O

2

is given as

32.00

g/mol

, we then have

0.5

=

√

32

l

g/mol

M

M

X

Using algebra to solve for

M

M

X

:

0.5

=

√

32

l

g/mol

√

M

M

X

√

M

M

X

=

√

32

l

g/mol

0.5

M

M

X

=

(

√

32

l

g/mol

0.5

)

2

=

128

g/mol

The molar mass of the unknown gas is thus

128

g/mol

A gas close to this value is

iodine

, with molar mass

126.90

g/mol

.

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.