For the reaction: CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

the value of Kc is 1.845 at a specific temperature. We place 0.500mol CO and 0.500mol H2O in a 1.00L container at this temperature and allow the reaction to reach equilibrium. Determine the equilibrium concentration of all species present in the container.

The equilibrium constant for CO now

= 0.212 M

For H₂O

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

Explanation:

The chemical equation for the reaction is:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

The ICE Table for this reaction can be represented as follows:

                   CO(g)      +   H2O(g)   ⇌    CO2(g)   +     H2(g)

Initial            0.5                0.5                   -                      -

Change        -x                   -x                      + x                + x

Equilibrium   0.5 -x           0.5 - x

The equilibrium constant

where;

1.3583 (0.5-x) = x

0.67915  - 1.3583x = x

0.67915  = x +  1.3583x

0.67915 = 2.3583x

x = 0.67915/2.3583

x = 0.2880

The equilibrium constant for CO now = 0.5 - x

= 0.5 -  0.2880

= 0.212 M

For H₂O = 0.5 - x

= 0.5 -  0.2880

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.