Calculate the volume in liters of a 29.8 g/dL nickel(II) chloride solution that contains 131. G of nickel(II) chloride . Be sure your answer has the correct number of significant digits.

0.44 L.

Explanation:

Density of nickel(II) chloride = 29.8 g/dL.

Mass of nickel(II) chloride = 131 g

Volume of nickel(II) chloride =?

Next, we shall convert 29.8 g/dL to g/L. This can be obtained as follow:

Recall:

1 g/dL = 10 g/L

Therefore,

29.8 g/dL = 29.8 x 10 = 298 g/L

Therefore, 29.8 g/dL is equivalent to 298 g/L.

Finally, we shall determine the volume of nickel(II) chloride as follow:

Density of nickel(II) chloride = 298 g/L

Mass of nickel(II) chloride = 131 g

Volume of nickel(II) chloride =?

Density = mass /volume

298 = 131/Volume

Cross multiply

298 x Volume = 131

Divide both side by 298

Volume = 131/298

Volume = 0.44 L

Therefore, the volume of of nickel(II) chloride is 0.44 L

it means there are 3 atoms of oxygen