The radius of a aluminum atom is 143 pm. How many aluminum atoms would have to be laid side by side to span a distance of 2.36 mm?

1.65x10⁷ atoms of Al have to be laid side by side to span a distance of 2.36mm

Explanation:

We can assume Aluminium atoms as balls ordered side by side. As the radius of 1 atom is 143pm = 143x10⁻¹²m, the space that 1 atom occupies is 2 radius = 286x10⁻¹²m. That means to occupy 2.36mm = 2.36x10⁻³ you require:

2.36x10⁻³m ₓ ( 1 atom Al / 143x10⁻¹²m) =

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

just did the assignment and the answer was #1 +2 n