From a sample with n=20, the mean number of televisions per household is 2 with a standard deviation of 1 television. using chebychev's theorem, determine at least how many of the households have between 0 and 4 televisions. at least nothing of the households have between 0 and 4 televisions.

At least 15 households have between 0 and 4 televisions.

Step-by-step explanation:

Chebychev's Theorem:

P(|X-μ|>kσ)≤

μ= mean

σ= standard deviation

k= number of typical deviations

It is also expressed as:

P(μ-kσ<X<μ+kσ)≥

Using Chebychev's Theorem, we determine:

P(0<X<4)

μ-kσ=0 ⇒ 2-k·1=0 ⇒k=2

μ+kσ=4 ⇒ 2+k·1=4 ⇒k=2

P(0<X<4)==0.75

For a sample n=20,

0.75×20=15

At least 15 households have between 0 and 4 televisions.

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.

answer: options?

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