You start with 6 moles of an acid, 2 moles dissociate into the conjugate base, what is the percent ionization

33 %

Explanation:

Step 1: Given data

Initial moles of the acid (nHA(0)): 6 mol

Moles of the conjugate base at equilibrium (nA⁻(eq))

Step 2: Write the balanced generic acid dissociation reaction

HA(aq) ⇄ A⁻(aq) + H⁺(aq)

Step 3: Calculate the percent ionization

We will use the following expression.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

i think its 100

i hope this !