The concentration of 1130+ in a solution is found to be 1.75 X 10-8 M 250C. Find [OH].

[OH] = 6.31 * 10^-7 M

Explanation:

Mathematically;

pH + pOH = 14

Mathematically;

pH = -log [H3O+]

also;

pOH = -log [OH]

From the question; [H3O+] = 1.75 * 10^-8 M

pH = -log [1.75 * 10^-8]

pH = 7.76

since pH is normally given to 1 decimal place

we can say pH = 7.8

Now;

pH + pOH = 14

pOH = 14-7.8

pOH = 6.2

now pOH = -log [OH]

[OH] = -antilog 6.2

[OH] = 6.31 * 10^-7 M