Cadmium (Cd) is reported to be much more toxic as the free metal (Cd^2+) than when complexed with ligands. The total soluble Cd concentration (Cgamma, Cd = [Cd^2+] 4- the sum of all soluble Cd complexes) in a water is measured to be 10^-4M. In order to ensure that the toxicity of Cd is small, it is desirable to have Cd^2+ be less than 10^-7 M. An environmental engineer suggests adding 0.5 M NaCl to complex the Cd^2+. Ignore activity corrections and the formation of any solids. Consider only the complexes of chloride with cadmium-there are 4 (log beta1 = 2.0, log beta2 = 2.6, log beta3 = 2.4, and log beta4 = 1.7).
A. Will this help keep [Cd^2+] below 10^-7 M?
B. What is [Cd^2+]?

the answer is true.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

you need to stop taking that class