How would you solve this?
"Calculate the amount of energy transferred if only 650.50 grams of sulfur trioxide (SO3) gas were produced. (Remember the ∆H = -396.8 kJ is part of the balanced equation)"
balanced equation: 2 SO2 (g) + O2(g) ⇌ 2 SO3 (g) ∆H = -396.8 kJ

1.6×10^3 KJ

Explanation:

We must first calculate the number of moles corresponding to 650.50g of sulphur trioxide.

Number of moles = mass of sulphur trioxide/ molar mass of sulphur trioxide

Molar mass of sulphur trioxide= 80.066 g/mol

Given mass of sulphur trioxide= 650.50g

Number of moles = 650.50g / 80.066 g/mol

Number of moles = 8.124 moles of sulphur trioxide

Now from the balanced reaction equation;

Formation of 2 moles of sulphur trioxide evolves 396.8KJ of energy.

Therefore formation of 8.124 moles of sulphur trioxide will evolve;

8.124moles × 396.8 KJ /2 moles = 1611.8KJ or 1.6×10^3 KJ

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: