A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?
Use M subscript i V subscript 1 equals M subscript f V subscript f..
Measure 114 mL of the 1.75 M solution, and dilute it to 1.00 L.
Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.
Measure 8.75 mL of the 1.75 M solution, and dilute it to 2.00 L.
Measure 8.75 mL of the 0.100 M solution, and dilute it to 2.00 L.

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.